leqalign Adjoint - of - the - matrix - N bmatrix -4 -3 -3 11 - 0 - 1 4 - 4 - 3-endbmatrix isA- 2 NB- NC- - ND- None of these

The correct option is B N Cofactors of the matrix N = [ 4 amp; 3 amp; 3; 1 amp; 0 amp; 1; 4 amp; 4 amp; 3 ] are c_11= 4,c_ ...

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Byju's Answer

Standard X

Mathematics

Identity Matrix

leqalign Adjo...

Question

$\begin{matrix} A d j o i n t o f t h e m a t r i x N ⎡ ⎢ ⎣ \begin{matrix} - 4 & - 3 & - 3 1 & 0 & 1 4 & 4 & 3 \end{matrix} ⎤ ⎥ ⎦ \end{matrix}$ is

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-N

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None of these

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Solution

The correct option is A
N

$\begin{matrix} C o f a c t o r s o f t h e m a t r i x N = ⎡ ⎢ ⎣ \begin{matrix} - 4 & - 3 & - 3 1 & 0 & 1 4 & 4 & 3 \end{matrix} ⎤ ⎥ ⎦ a r e c_{11} = - 4, c_{12} = 1, c_{13} = 4; c_{21} = - 3, c_{22} = 0, c_{23} = 4; c_{31} = - 3, c_{32} = 1, c_{33} = 3 \end{matrix}$

$\begin{matrix} a d j N = ⎡ ⎢ ⎣ \begin{matrix} - 4 & - 3 & - 3 1 & 0 & 1 4 & 4 & 3 \end{matrix} ⎤ ⎥ ⎦ = N \end{matrix}$

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Similar questions

$\begin{matrix} A d j o i n t o f t h e m a t r i x N ⎡ ⎢ ⎣ \begin{matrix} - 4 & - 3 & - 3 1 & 0 & 1 4 & 4 & 3 \end{matrix} ⎤ ⎥ ⎦ \end{matrix}$ is [MP PET 1989]

Q. If

⎡ ⎢ ⎣ \begin{matrix} 1 & α & 3 1 & 3 & 3 2 & 4 & 4 \end{matrix} ⎤ ⎥ ⎦

is the adjoint of a

3 \times 3

matrix

A

and

| A | = 4

, then

α

is equal to:

Q. If

P = ⎡ ⎢ ⎣ \begin{matrix} 1 & α & 3 1 & 3 & 3 2 & 4 & 4 \end{matrix} ⎤ ⎥ ⎦

is the adjoint of a

3 \times 3

matrix

A

and

| A | = 4

, then

α

is equal to

Q. If matrix

P = ∣ ∣ ∣ ∣ \begin{matrix} 1 & α & 3 1 & 3 & 3 2 & 4 & 4 \end{matrix} ∣ ∣ ∣ ∣

is the adjoint of a

3 \times 3

matrix A and |A| = 4, then

α

is equal to

Q. The adjoint of the matrix

⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 1 & 1 & 1 2 & 3 & 4 \end{matrix} ⎤ ⎥ ⎦

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Adjoint of the matrix N⎡⎢⎣−4−3−3101443⎤⎥⎦ is

The correct option is A N Cofactors of the matrix N=⎡⎢⎣−4−3−3101443⎤⎥⎦are c11=−4,c12=1,c13=4;c21=−3,c22=0,c23=4;c31=−3,c32=1,c33=3 adj N=⎡⎢⎣−4−3−3101443⎤⎥⎦=N

$\begin{matrix} A d j o i n t o f t h e m a t r i x N ⎡ ⎢ ⎣ \begin{matrix} - 4 & - 3 & - 3 1 & 0 & 1 4 & 4 & 3 \end{matrix} ⎤ ⎥ ⎦ \end{matrix}$ is