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Question
Equal amounts of two gases of molecular weight 4 and 40 are mixed. The pressure of the mixture is 1.1 atm. The partial pressure of the light gas in this mixture is
Equal amounts of two gases of molecular weight 4 and 40 are mixed. The pressure of the mixture is 1.1 atm. The partial pressure of the light gas in this mixture is
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Solution
The correct option is C 1 atm
Use dalton's law of partial pressures.
Take the equal mass to be 'm'
Total moles of gases added: m/4 +m/40
Since no reaction is happening, number of moles are proportional to the partial pressures.
Hence, the partial pressures are in the ratio 10:1, and the partial pressure of the lighter gas (4g/mol) would be 1 atm.
Use dalton's law of partial pressures.
Take the equal mass to be 'm'
Total moles of gases added: m/4 +m/40
Since no reaction is happening, number of moles are proportional to the partial pressures.
Hence, the partial pressures are in the ratio 10:1, and the partial pressure of the lighter gas (4g/mol) would be 1 atm.
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