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Question

Equal charges each of 20 micro column are placed at x=0,2,4,8,16 cm on x-axis . find the force experienced by the charge at x=2 cm

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Solution

Given situation can be represented as


Force on charge B at x = 2 is towards right due to the charge at A and due to the charge at C, D, and E it is towards left.

Charge q = 20×106C

We can write,

FBA=kq2r12=kq24×104

FBC=kq2r21=kq24×104

FBD=kq236×104

FBE=kq2196×104

Now we can write

Fnet=(FBC+FBD+FBE)FAB

Now putting all the values

Fnet=kq2104[14+136+1196]

Putting all the values

Fnet=9×109×20×106×20×106104[14+136+1196]

After solving we get

Fnet=1.18×103N

Hence the net force on the particle at the x = 2 position is Fnet=1.18×103N




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