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Magnetic Field

Equal current...

Question

Equal current I flows in two segments of a circular loop in the directions shown in figure. Radius of the loop is a. Magnetic field at the centre of the loop is

A

Zero

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B

$(\frac{2 π - θ}{π}) \frac{μ_{0} i}{2 a}$

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C

(\frac{π - θ}{π}) \frac{μ_{0} i}{2 a}

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D

$(\frac{θ}{π}) \frac{μ_{0} i}{2 a}$

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Solution

The correct option is B
$(\frac{2 π - θ}{π}) \frac{μ_{0} i}{2 a}$

Magnetic field due to ADB is

(perpendicular to paper inwards)

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