Equal force F acts on isolated bodies X and Y as shown in figure. The mass of Y is three times that of X. The magnitude of the acceleration of X is ..........
A
Three times that of Y
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B
1/3 that of Y
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C
Nine times that of Y
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D
1/9 that of Y
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Solution
The correct option is A Three times that of Y F=ma a=Fm Let mass of X is m, so mass of Y will be 3m
The acceleration of X, AX=Fm and acceleration of Y, AY=F3m.
hence, The magnitude of the acceleration of X is Three times that of Y