Equal forces $¯ ¯¯ ¯ F$ act on isolated bodies A and B as shown. The mass of B is three times that of A. The magnitude of the acceleration of A is :

Three times that of B

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1/3 that of B

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Nine times that of B

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1/9 that of B

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Solution

The correct option is A Three times that of B
Given $F_{A} = F_{B}$
$m_{B} = 3 m_{A}$
$m_{A} a_{A} = m_{B} a_{B}$
$a_{A} = 3 a_{B}$

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Equal forces ¯¯¯¯F act on isolated bodies A and B as shown. The mass of B is three times that of A. The magnitude of the acceleration of A is :

The correct option is A Three times that of BGiven FA=FBmB=3mAmAaA=mBaBaA=3aB

Equal forces $¯ ¯¯ ¯ F$ act on isolated bodies A and B as shown. The mass of B is three times that of A. The magnitude of the acceleration of A is :

The correct option is A Three times that of B
Given $F_{A} = F_{B}$
$m_{B} = 3 m_{A}$
$m_{A} a_{A} = m_{B} a_{B}$
$a_{A} = 3 a_{B}$