Equal masses of ethene and butene have their total translational kinetic energy in the ratio $2 : 1$ , then their absolute temperatures are in the ratio :

2 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $1 : 1$
The expression for the translational kinetic energy is $E = \frac{3}{2} \times \frac{m a s s}{m o l e c u l a r w e i g h t} R T_{e}$ .
The expression for the translational kinetic energy of ethene is $E_{e} = \frac{3}{2} \times \frac{M}{28} R T_{e}$ .
The expression for the translational kinetic energy of butene is $E_{b} = \frac{3}{2} \times \frac{M}{56} R T_{b}$ .

Dividing both equation,

$\frac{E_{e}}{E_{b}} = \frac{56}{28} \frac{T_{e}}{T_{b}}$ .

$\frac{2}{1} = \frac{56}{28} \frac{T_{e}}{T_{b}}$ .

$\frac{T_{e}}{T_{b}} = \frac{1}{1}$ .

Thus, their absolute temperatures are in the ratio 1:1.

Suggest Corrections

Similar questions

Two bodies of masses 1 kg and 2 kg have equal momentum. Then, the ratio of their kinetic energies is

2 : 1

1 : 2

2 : 1

2 : 1

2 : 1

1 : 2

Masses of two particles having same kinetic energies are in the ratio 1 : 2 then, their de-broglie wavelengths are in ratio:

Join BYJU'S Learning Program