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Heat of Reaction

Equal masses ...

Question

Equal masses of $H_{2}$ , He and ${C H}_{4}$ are mixed in empty container at 300 K, when total pressure is 2.6 atm. The partial pressure of $H_{2}$ in the mixture is:-
choose answer:
1) 0.5 atm
2) 1.22 atm
3) 0.8 atm
4) 0.2 atm

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Solution

Mass of each gas=m
moles of $H_{2}$ = $\frac{m}{2}$
moles of He= $\frac{m}{2}$
moles of $C H_{4}$ = $\frac{m}{16}$
Total moles=n= $\frac{17 m}{16}$
Partial pressure of $H_{2}$ = $\frac{m o l e s o f H_{2}}{T o t a l m o l e s} \times T o t a l p r e s s u r e$
$\frac{\frac{\frac{m}{2}}{17 m}}{16} \times 2.6$
$\frac{8}{17} \times 2.6$
$1.22$ atom
Partial pressure of $H_{2} = 1.22$ atm

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