Question

Equal masses of $H_2,O_2$ and methane have been taken in a container of volume $V$ at temperature ${27}^{o}C$ in identical conditions. The ratio of the volumes of gases $H_2:O_2$: methane would be:

• A. 8:16:1
• B. 16:8:1
• C. 16:1:2
• D. 8:1:2

Answer 1

The correct option is C 16:1:2

Assume that 100 g each of hydrogen, oxygen and methane are present.

The volume of gases is directly proportional to the number of moles of gases.

The molar mass of hydrogen, oxygen and methane are 2 g/mol, 32 g/mol and 16 g/mol respectively.

The number of moles of hydrogen, oxygen and methane are $\frac{100}{2}$, $\frac{100}{32}$ and $\frac{100}{16}$ respectively.

The ratio of the volumes of hydrogen, oxygen and methane will be $\frac{100}{2}:\frac{100}{32}:\frac{100}{16}=\frac{1}{1}:\frac{1}{16}:\frac{1}{8}=16:1:2$.

Option C is correct.