Question

Equal masses of $H_2,O_2$ and methane have been taken in a container of volume V at temperature ${27}^{o}C$ in identical conditions. The ratio of the volumes of gases $H_2:O_2$: methane would be___________.

• A. 8:16:1
• B. 16:8:1
• C. 16:1:2
• D. 8:1:2

Answer 1

Answer: (C)

16:1:2

Let the mass of each gas be $w$

so,

Number of moles of $H_2=\frac{w}{2}$

Number of moles of $O_2=\frac{w}{32}$

Number of moles of $C{H}_2=\frac{w}{16}$

then,

Volume of $H_2=\frac{w}{2}\times 22.4L$

Volume of $O_2=\frac{w}{32}\times 22.4L$

Volume of $C{H}_2=\frac{w}{16}\times 22.4L$

therefore,

$\frac{w/2}{w/32}=16for{H}_2$

$\frac{w/32}{w/32}=1for{O}_2$

$\frac{w/16}{w/32}=2forC{H}_2$

$Ratio=16:1:2$