Question

Equal masses of $H_2,O_2$ and methane have been taken in a container of volume $V$ at temperature ${27}^{o}C$ in identical conditions. The ratio of the volumes of gases $H_2:O_2:C{H}_4$ would be:

• A. $8:16:1$
• B. $16:8:1$
• C. $16:1:2$
• D. $8:1:2$

Answer 1

The correct option is C $16:1:2$

The no of moles of $H_2$=$\frac{w}{2}$

No. of moles of $O_2$ =$\frac{w}{32}$

No. of moles of $C{H}_4$=$\frac{w}{16}$

So the volume of $H_2$$=\frac{w}{2}\times 22.4L$

Volume of $O_2$$=\frac{w}{32}\times 22.4L$

Volume of $C{H}_4$ $=\frac{w}{16}\times 22.4L$

So the ratio will be $\frac{1}{2}:\frac{1}{32}:\frac{1}{16}$

$=16:1:2$