Question

Equal masses of $H_2,O_2$ and methane have been taken in a container of volume V at temperature ${27}^{o}C$ in identical conditions. The ratio of the volumes of gases $H_2:O_2:C{H}_4$ would be

• A. $8:16:1$
• B. $16:8:1$
• C. $16:1:2$
• D. $8:1:2$

Answer 1

The correct option is C $16:1:2$

According to Avogadro's hypothesis,
$\text{Volume of a gas (V)}\propto \text{number of moles (n)}$
Therefore, the ratio of the volumes of gases can be determined in terms of their moles.
The ratio of volumes of $H_2:O_2:C{H}_4$ is given by
$V_{H_2}:V_{O_2}:V_{C{H}_4}=n_{H_2}:n_{O_2}:n_{C{H}_4}$
Masses are equal.
$V_{H_2}:V_{O_2}:V_{C{H}_4}=\frac{m}{2}:\frac{m}{32}:\frac{m}{16}$
$V_{H_2}:V_{O_2}:V_{C{H}_4}=16:1:2$