Question

Equal masses of oxygen, hydrogen, and methane are taken in a container in identical condition. Find the ratio of volumes of the gases.

• A. 1: 32 :2
• B. 1 : 16: 2
• C. 1 : 1: 1
• D. 1: 16 :1

Answer 1

The correct option is B 1 : 16: 2

The molecular weights of a given mixture of gases are

1. Oxygen = 32

2. Hydrogen = 2

3. Methane = 16

Since masses are equal, assume mass as x,

So By using formula, no of moles = $\frac{mass}{molecularweight}$

$n_{O_2}=\frac{x}{32}$ : $n_{H_2}=\frac{x}{2}$ : $n_{C{H}_4}=\frac{x}{16}$

ratio is $1:16:2$