Question

Equal masses of oxygen, hydrogen and methane are taken in a container under identical conditions. Find the ratio of their volumes.

• A. $3:16:2$
• B. $2:16:1$
• C. $5:16:2$
• D. $1:16:2$

Answer 1

The correct option is D $1:16:2$

Let assume mass=x

No. of moles $=n\left(O_2\right)=\frac{x}{32}$

$n\left(H_2\right)=\frac{x}{2}$

$n\left(C{H}_4\right)=\frac{x}{16}$

Now ,divide every value by smallest value which is $\frac{x}{32}$

$\frac{\frac{x}{32}}{\frac{x}{32}}:\frac{\frac{x}{2}}{\frac{x}{32}}:\frac{\frac{x}{16}}{\frac{x}{32}}=O_2:H_2:C{H}_4\Rightarrow 1:16:2$