Equal masses of oxygen, hydrogen and methane are taken in container in identical condition. Find the ratio of the volumes of the gases
Step 1:
Let assume the mass = x
Number of moles = n(O2)=x32
n(H2)=x2
n(CH4)=x16
Step 2:
Now ,divide every value by smallest value which is x32
O2:H2:CH4
x32x32 : x2x32 : x16x32
1 : 16 : 2
Hence, option (B) is correct.