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Dalton's Law of Partial Pressures

Equal masses ...

Question

Equal masses of $S O_{2}$ and $O_{2}$ are kept in a vessel at $27^{0}$ C.The total pressure is 2 atm. The partial pressure of $S O_{2}$ (in atm) is:

A

2/3

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B

0

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C

3/2

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D

None of these

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Solution

The correct option is A 2/3
Suppose 64 g each of $S O_{2}$ and $O_{2}$ are present.
This corresponds to $\frac{64}{64} = 1$ mole of $S O_{2}$ and $\frac{64}{32} = 2$ moles of $O_{2}$
The mole fraction of $S O_{2}$ will be $\frac{1}{1 + 2} = \frac{1}{3}$ .
The partial pressure of $S O_{2}$ will be $\frac{1}{3} \times 2 = \frac{2}{3}$

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