Equal moles of hydrogen and oxygen gases are placed in a container with a pin-hole through which both can escape. How many moles of Oxygen gas escape in the time required for half a mole of the hydrogen to escape?
Step 1:
Assume 1 mole of hydrogen and 1 mole of oxygen gases are placed in a container with a pin-hole through which both can escape.
By using Graham's Law:
nO2nH2=√MH2MO2
Step 2:
⇒ nO20.5=√232
∴ nO2=18
Therefore, the fraction of the oxygen that escapes in the time required for one-half of the hydrogen to escape is 18
Hence, option (D) is correct.