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Question

Equal volume of following solution are mixed, in which case the pH of resulting solution will be average value of pH two solution.

A
pH=2HCI&pH=12NaOH
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B
pH=2 HCI &pH=4 HCI
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C
pH=2HCN&pH=12NaOH ka of HCN=1010
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D
pH=5 CH3COOH & pH=9 NH3(aq) Ka(CH3COOH)=Kb(NH3)(aq)
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Solution

The correct option is A pH=2HCI&pH=12NaOH
pH=2,pOH=12
HCl NaOHpH=1412=2
pH=pH1+pH22=2+22=2 .

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