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Question

Equal volume of two solution having pH=2 and pH=10 are mixed together at 90oC. Then pH of resulting solution is:

[Take Kw at 90oC=1012]

A
2 + log 2
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B
10 log 2
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C
7
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D
6
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Solution

The correct option is C 6
The ionic product of water at 90oC is 1012.
Hence pKw=12. Thus the pH at the neutral point will be 6.

When equal volumes of solutions having pH 2 ([H+]=0.01M) and pH 10([OH]=0.01M) are added at 90oC, a neutral solution with pH 6 is obtained.

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