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Question
Equal volumes of 0.06 M Na2SO4(aq) and 0.06 M KHSO4(aq) are mixed together. Calculate pH of the resuting solution.
Given : KaHSO−4=2×10−2
Given : KaHSO−4=2×10−2
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Solution
The correct option is A 2
HSO−40.03−x2×10−2−−−−−→SO−240.03+x+H+x
2×10−2=(0.03+x)x(0.03−x)
or,6×10−4−0.02x=x2+0.03x
or,x2+0.05x−6×10−4=0
or,x=−0.05±√25×10−4+24×10−42=−0.05+0.072=0.022=0.01
⇒[H+]=0.01⇒RHI2pH=−log[10−2]pH=2
HSO−40.03−x2×10−2−−−−−→SO−240.03+x+H+x
2×10−2=(0.03+x)x(0.03−x)
or,6×10−4−0.02x=x2+0.03x
or,x2+0.05x−6×10−4=0
or,x=−0.05±√25×10−4+24×10−42=−0.05+0.072=0.022=0.01
⇒[H+]=0.01⇒RHI2
pH=−log[10−2]
pH=2
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