Equal volumes of $0.1$ M ${A g N O}_{3}$ and $0.2$ M $N a C l$ solutions are mixed. The concentration of nitrate ion in the resultant mixture will be:

0.1

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0.2

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0.05

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0.15

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Solution

The correct option is C $0.05$ M
Consider equal volume, V of $A g N O_{3}$ and $N a C l$ are mixed.

$A g N O_{3} + N a C l \to A g C l + N a N O_{3}$
0.1V 0.2V 0 0 at initial
0 0.1V 0.1V 0.1V at equilibrium

Total volume $= V + V = 2 V$

Concentration of $N O_{3}^{-}$ ion in the mixture is:

$M o l a r i t y = \frac{0.1 V}{2 V}$ $= 0. 05 M$

Hence, option $C$ is correct.

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