Equal volumes of 1 M each of KMnO 4 and K 2 Cr 2 O 7 are used to oxidise Fe II solution in acidic medium- The amount of Fe oxidized will be-A- Equal with both oxidizing agentsB- More with K 2 Cr 2 O 7C- Cannot be determinedD- More with KM nO 4

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equivalent Mass

Equal volumes...

Question

Equal volumes of 1 M each of $K M n O_{4}$ and $K_{2} C r_{2} O_{7}$ are used to oxidise Fe(II) solution in acidic medium. The amount of Fe oxidized will be:

More with

K M n O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Equal with both oxidizing agents

No worries! We‘ve got your back. Try BYJU‘S free classes today!

More with

K_{2} C r_{2} O_{7}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Cannot be determined

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C More with $K_{2} C r_{2} O_{7}$
The 'n' factor of $K M n O_{4}$ is 5 while that of $K_{2} C r_{2} O_{7}$ is 6. So for the same number of moles, $K_{2} C r_{2} O_{7}$ will have greater equivalence than $K M n O_{4} .$

Suggest Corrections

Similar questions

Equal volumes of 1 M each of $K M n O_{4}$ and $K_{2} C r_{2} O_{7}$ are used to oxidise Fe(II) solution in acidic medium. The amount of Fe oxidized will be :

Q. If equal volumes of

1 M

K M n O_{4}

and

1 M

K_{2} C r_{2} O_{7}

solutions are used to oxidise

F e^{2 +}

in acidic medium, then

F e^{2 +}

will be oxidised

If equal volumes of 0.1 M $K M n O_{4}$ and $0.1 M K_{2} C r_{2} O_{7}$ solutions are allowed to oxidise $F e^{2 +}$ to $F e^{3 +}$ in acidic medium, then $F e^{2 +}$ oxidized will be:

Q. Ratio of moles of Fe (II) oxidized by equal volumes of equimolar

K M n O_{4}

and

K_{2} C r_{2} O_{7}

solutions in acidic medium will be :

Q. Ratio of moles of Fe (II) oxidized by equal volumes of equimolar

K M n O_{4}

and

K_{2} C r_{2} O_{7}

solutions in acidic medium will be:

Join BYJU'S Learning Program

Equal volumes of 1 M each of KMnO4 and K2Cr2O7 are used to oxidise Fe(II) solution in acidic medium. The amount of Fe oxidized will be:

The correct option is C More with K2Cr2O7The 'n' factor of KMnO4 is 5 while that of K2Cr2O7 is 6. So for the same number of moles, K2Cr2O7 will have greater equivalence than KMnO4.

Equal volumes of 1 M each of $K M n O_{4}$ and $K_{2} C r_{2} O_{7}$ are used to oxidise Fe(II) solution in acidic medium. The amount of Fe oxidized will be:

The correct option is C More with $K_{2} C r_{2} O_{7}$
The 'n' factor of $K M n O_{4}$ is 5 while that of $K_{2} C r_{2} O_{7}$ is 6. So for the same number of moles, $K_{2} C r_{2} O_{7}$ will have greater equivalence than $K M n O_{4} .$