Question

Equal volumes of 1 M each of $KMn{O}_4$ and $K_{2}C{r}_2{O}_7$ are used to oxidise Fe(II) solution in acidic medium. The amount of Fe oxidized will be :

• A. more with $KMn{O}_4$
• B. equal with both oxidizing agents
• C. more with $K_{2}C{r}_2{O}_7$
• D. cannot be determined

Answer 1

Answer: (C)

more with $K_{2}C{r}_2{O}_7$

$n_f$ of $K_{2}C{r}_2{O}_7=6$

$n_f$ of $KMn{O}_4=5$

As the $n_f$ for $K_{2}C{r}_2{O}_7$ is more therefore more equivalents will be present hence more Fe can be oxidised by $K_{2}C{r}_2{O}_7$.