HCl = d NaOH = 1.5 d HCl in 10 ml of it = 10d/36.5 NaOH in 10 ml of it =10 × 1.5d/40= 15d/40 NaOH gt; HCl ...

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Arrhenius Acid

Equal volumes...

Question

Equal volumes of 10% $\frac{v}{v}$ of HCl is mixed with 10% $\frac{v}{v}$ NaOH solution. If density pure NaOH is 1.5 times that of pure HCl then the resultant solution be

Basic

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Neutral

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Acidic

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Can't be predicted

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Solution

The correct option is A
Basic

HCl = d

NaOH = 1.5 d

HCl in 10 ml of it = $\frac{10 d}{36.5}$

NaOH in 10 ml of it = $\frac{10 \times 1.5 d}{40}$ = $\frac{15 d}{40}$

NaOH> HCl

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Equal volumes of 10%vv of HCl is mixed with 10%vv NaOH solution. If density pure NaOH is 1.5 times that of pure HCl then the resultant solution be

The correct option is A Basic HCl = d NaOH = 1.5 d HCl in 10 ml of it = 10d36.5 NaOH in 10 ml of it =10× 1.5d40= 15d40 NaOH> HCl

Equal volumes of 10% $\frac{v}{v}$ of HCl is mixed with 10% $\frac{v}{v}$ NaOH solution. If density pure NaOH is 1.5 times that of pure HCl then the resultant solution be

The correct option is A
Basic

HCl = d

NaOH = 1.5 d

HCl in 10 ml of it = $\frac{10 d}{36.5}$

NaOH in 10 ml of it = $\frac{10 \times 1.5 d}{40}$ = $\frac{15 d}{40}$

NaOH> HCl