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Enthalpy of Neutralisation

Equal volumes...

Question

Equal volumes of 1M HCl& 1M $H_{2} S O_{4}$ are neutralized by 1M NaOH solution and x & y KJ/equivalent of heat are liberated respectively. Which of the following relations is correct?

x = 2y

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x = 3y

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x = 4y

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x =

\frac{1}{2}

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Solution

The correct option is D x = $\frac{1}{2}$ y
We can clearly see that, $H_{2} S O_{4}$ gives 2 moles H+ while HCl gives 1 mole H+ from 1 mole after ionization. Hence, $H_{2} S O_{4}$ will release double amount of heat as compared to HCl,

$∴$ y = 2x
$∴$ x = 1/2 y

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Equal volumes of 1M HCl& 1M H2SO4 are neutralized by 1M NaOH solution and x & y KJ/equivalent of heat are liberated respectively. Which of the following relations is correct?

The correct option is D x = 12 yWe can clearly see that, H2SO4 gives 2 moles H+ while HCl gives 1 mole H+ from 1 mole after ionization. Hence, H2SO4 will release double amount of heat as compared to HCl, ∴ y = 2x ∴ x = 1/2 y

Equal volumes of 1M HCl& 1M $H_{2} S O_{4}$ are neutralized by 1M NaOH solution and x & y KJ/equivalent of heat are liberated respectively. Which of the following relations is correct?

The correct option is D x = $\frac{1}{2}$ y
We can clearly see that, $H_{2} S O_{4}$ gives 2 moles H+ while HCl gives 1 mole H+ from 1 mole after ionization. Hence, $H_{2} S O_{4}$ will release double amount of heat as compared to HCl,

$∴$ y = 2x
$∴$ x = 1/2 y