Question

Equal volumes of molar $HCl$ and $H_{2}S{O}_4$ are neutralised by dilute $NaOH$ solution and $x$ Kcal and $y$ Kcal of heat are liberated respectively. Which of the following is true?

• A. $x=y$
• B. $x=\frac{y}{2}$
• C. $x=\frac{y}{3}$
• D. $x=2y$

Answer 1

The correct option is B $x=\frac{y}{2}$

Double heat will be evolved in case of $H_{2}S{O}_4$ as it has two moles of hydrogen.

Heat evolved for $H_{2}S{O}_4=2\times$ heat evolved for $HCl$.

$\therefore y=2x$

$⟹x=\frac{y}{2}$