Equal volumes of two gases A and B diffuse through a porous pot in 20s and 10s, respectively .If the molar mass of A be $80 g m o l^{- 1}$ ,Find the molar mass of B.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C

$\frac{r_{A}}{r_{B}} = \frac{\frac{V}{20}}{\frac{V}{10}} = \sqrt{\frac{M_{B}}{M_{A}}}$

Where rate(r) = $\frac{V o l u m e d i f f u s e s}{T i m e i n t e r v a l}$ .

Simplifying we get,

$\frac{10}{20} = \sqrt{\frac{M_{B}}{80}} \Rightarrow M_{B} = \frac{100}{400} \times 80 \Rightarrow 20 g m o l^{- 1}$

Suggest Corrections

Similar questions

Equal volumes of two gases A and B diffuse through a porous pot in 20s and 10s, respectively .If the molar mass of A be $80 g m o l^{- 1}$ ,Find the molar mass of B.

Equal volumes of two gases A and B diffuse through a porous pot in $20$ and $10$ seconds respectively. If the molar mass of A is $80$ , find the molar mass of B.

Q. Under similar conditions, 390 cm