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Gay Lussac's Law

Equal volumes...

Question

Equal volumes of two gases which do not react together are enclosed in separate vessels. Their pressures are 100 mm and 400 mm respectively. If the two vessels are joined together, then what will be the pressure of the resulting mixture (temperature remaining constant)?

A

125 mm

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B

500 mm

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C

1000 mm

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D

250 mm

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Solution

The correct option is D 250 mm
According to Boyle's law,

$P_{1} V_{1} + P_{2} V_{2} = P_{t} V_{t}$

Given, $V_{1} = V_{2} = V; V_{t} = 2 V;$

$P_{1} = 100 m m P_{2} = 400 m m$

$\Rightarrow$ $P_{t} = \frac{100 + 400}{2} = 250 m m$

Hence, option D is correct.

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