wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Equal volumes of two immiscible liquids of densities p and 2p are filled in a vessel as shown in the figure. Two small holes are punched at depthh2and3h2 from the surface of lighter liquid. If v1 and v2 are the velocities of efflux at these holes, then v1v2 will be:


1190877_5be93abd8d9e418daf0f9419f5f96e67.PNG

Open in App
Solution

We have,

v1=2g×(h2)

v1=gh

Now, by using Bernoulli’s theorem

ρgh+2ρg(h2)=12(2ρ)v22

v2=2gh

Now, the value of v1v2

v1v2=gh2gh

v1v2=12

Hence, this is the required solution


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Bernoulli's Principle
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon