Question

Equal volumes of two isotonic solutions are mixed. The osmotic pressure of the final mixture is :

• A. same as initial
• B. half of initial
• C. twice of initial
• D. none of these

Answer 1

The correct option is A same as initial

Equal volumes of two isotonic solutions are mixed.

${\pi }_{resultant}=\frac{{\pi }_1{V}_1+{\pi }_2{V}_2}{V_1+V_2}=\pi$

Note: ${\pi }_1={\pi }_2=\pi$ and $V_1=V_2=V$ are given.

Option A is correct.