Question

Equal weights of $C{H}_4$ and $H_2$ are mixed in an empty container at ${25}^{o}C$. The fraction of total pressure exerted by $H_2$ is:

• A. $\frac{1}{2}$
• B. $\frac{8}{9}$
• C. $\frac{1}{9}$
• D. $\frac{1}{16}$

Answer 1

The correct option is B $\frac{8}{9}$

$\frac{P_{H_2}}{P}$ = Mole fraction of $H_2=\left(\frac{n_{H_2}}{n}\right)$

Mole fraction of $H_2=8:9$