Question

Equalise the denominators to determine which number is bigger and which smaller.

(3) $\frac{-15}{8},\frac{-9}{4}$

Answer 1

$\frac{-15}{8},\frac{-9}{4}$
L.C.M of 8 and 4 is 8.
$$\begin{gathered} \therefore \frac{-15}{8}=\frac{-15\times 1}{8\times 1}=\frac{-15}{8} \\ \mathrm{And}\frac{-9}{4}=\frac{-9\times 2}{4\times 2}=\frac{-18}{8} \end{gathered}$$
Denominators of both the numbers are same; therefore, the rational number with the greater numerator will be greater.
$$\begin{gathered} \therefore \frac{-15}{8}>\frac{-18}{8} \\ \therefore \frac{-15}{8}>\frac{-9}{4} \end{gathered}$$