Equation/equations of the planes bisecting the angles between the planes a1x+b1y+c1z+d1=0 and a2x+b2y+c2z+d2=0 is given by -
A
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B
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C
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D
None of these
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Solution
The correct option is C Given planes are a1x+b1x+c1x+d1=0....(i) a2x+b2x+c2x+d2=0....(ii) Let P(x,y,z) be a point on the plane bisecting the angle between these planes. Let PL and PM be the length of perpendiculars from P to planes (i) and (ii). So, PL = PM Or ∣∣
∣∣a1x+b1x+c1x+d1√a21+b21+c21∣∣
∣∣=∣∣
∣∣(a2x+b2x+c2x+d2)√(a22+b22+c22)∣∣
∣∣ Or a1x+b1x+c1x+d1√(a21+b21+c21)=±(a2x+b2x+c2x+d2)√(a22+b22+c22) This is the equation of planes bisecting the angles between the planes (i) and (ii).