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Question

Equation for a wave on a string is given by y=0.03sin(7.86x−2t) where y and x are in metres and t is in seconds. At t=0, find the value of displacement (approximately) for a particle on string at x=0.1 m.

A
2.1 cm
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B
4 cm
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C
3 cm
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D
7.86 cm
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Solution

The correct option is A 2.1 cm
Given, The equation of a wave on a string
y=0.03sin(7.86x2t)
Substituting t=0 and x=0.1 in above equation we get,
y=0.03sin(0.786)
Angle in radian can be converted to degrees by multiplying with 180π
y=0.03sin(0.786×180π)
y=0.03sin45, approx
y=0.021 m=2.1 cm

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