Question

Equation $H_{2}S+H_2{O}_2\to S+2H_{2}O$
Here $H_2{O}_2$ acts as an ___ agent.

• A. oxidising
• B. reducing
• C. bleaching
• D. hydrophobic

Answer 1

The correct option is A

oxidising

On the reactant side, the oxidation number is -2 and in the product side the oxidation number increases to 0 that means it has lost 2 electrons to $H_2{O}_2$ which eventually got reduced oxidizing sulphur in the reaction.

The increase in oxidation number of S shows the oxidising nature of $H_2{O}_2$.