Question

Equation I and II are given. Solve both and answer the following questions. (IBPS - RRBs)
I. 20x${}^2$ - 9x + 1 = 0
II. 12y${}^2$ - 7y + 1 = 0

• A. x > y
• B. x < y
• C. x $\ge$ y
• D. x $\le$ y
• E. Relationship between x and y cannot be established

Answer 1

The correct option is D x $\le$ y

Relationship between x and y cannot be established
Equation I: x = $\frac{4}{3}$ or $\frac{1}{5}$
Equation II: y = $\frac{1}{4}$ or $\frac{1}{3}$
So, a relationship cannot be established
So, x $\le$ y