Question

Equation I and II are given. Solve both and answer the following questions. (IBPS - RRBs)
I 3x${}^2$ - 13x + 12 = 0
II 3y${}^2$ - 7y + 2 = 0

• A.
  x > y
• B.
  x < y
• C.
  x $\ge$ y
• D.
  x $\le$ y
• E. Relationship between x and y cannot be established

Answer 1

The correct option is E Relationship between x and y cannot be established

Relationship between x and y cannot be established
Roots of the equation are:
Equation I: x = 3 or $\frac{4}{3}$
Equation II: y = 2 or $\frac{1}{3}$
So, a relationship cannot be established