Question

Equation I and II are given. Solve both and answer the following questions. (IBPS - RRBs)
I. x${}^2$ = 16
II 2y${}^2$ - 17y + 36 = 0

• A. x > y
• B.
  x < y
• C.
  x $\ge$ y
• D.
  x $\le$ y
• E. Relationship between x and y cannot be established

Answer 1

The correct option is D

x $\le$ y
Roots of the equation are:
Equation I: x = $\pm$ 4
Equation II: y = 4 or $\frac{9}{2}$
So, x $\le$ y