Equation of a circle whose centre is origin and radius is equal to the distance between the lines x = 1 and x = -1 is

x^{2} + y^{2} = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} + y^{2} = \sqrt{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} + y^{2} = 4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x^{2} + y^{2} = - 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $x^{2} + y^{2} = 4$
Radius = 2, C (0, 0)

Equation of circle can be found from this, Which will be $x^{2} + y^{2} = 4$

Suggest Corrections

Similar questions

7

x -

- 2

x -

2 x - y - 2 = 0

(3, - 2)

(- 2, 0)

(0, 0)

3 x + 4 y + 5 = 0

Join BYJU'S Learning Program