Equation of the line is y = 2x
(a) Point A lies on the line y = 2x so it satisfies the equation of the line.
y=2(−2)=−4
Hence y coordinate of point A is -4.
(b) To verify whether a circle of radius 5 centred at point A(-2, -4) passes through the point B(5, 5) it is enough to show that the distance between point A and B is 5.
AB=√(5+2)2+(5+4)2
=√49+81
=√130
≠5
Hence a circle of radius 5 centred at point A(-2, -4) does not pass through the point B(5, 5).
(c) Let (x1,y1) be the coordinates of centre C on line.
Therefore it satisfies the equation of line a y = 2x
∴y1=2x1
Also the distane between point B and C is radius that is 5.
So BC2=25
(x1−5)2+(y1−5)2=25
(x1−5)2+(2x1−5)2=25 [∵y1=2x1]
5x21−30x1+25=0
x21−6x1+5=0
(x1−5)(x1−1)=0
x1=5 or 1
y1=2x1=2(5)=10
y1=2x1=2(1)=2
The coordinates of point of C are (5, 10) or (1, 2).