Question

Equation of a line passing through (2,-1,1) and parallel to the line whose equation is $\frac{x-3}{2}=\frac{y+1}{7}=\frac{z-2}{-3}$is

• A. $\frac{x-2}{3}=\frac{y+1}{-1}=\frac{z-1}{2}$
• B. $\frac{x-2}{2}=\frac{y+1}{7}=\frac{z-1}{-3}$
• C. $\frac{x-2}{2}=\frac{y-1}{-1}=\frac{z+3}{1}$
• D. $\frac{x-3}{2}=\frac{y+1}{-1}=\frac{z-2}{1}$

Answer 1

The correct option is B $\frac{x-2}{2}=\frac{y+1}{7}=\frac{z-1}{-3}$

The required line passes through (2, -1,1) and its direction cosines are proportional to 2, 7, -3 so its
equation is $\frac{x-2}{2}=\frac{y+1}{7}=\frac{z-1}{-3}$