Equation of a normal to the curve $y = x log x$ , parallel to $2 x - 2 y + 3 = 0$ is

x + y = 3 e^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x - y = 3 e^{- 2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x - y = 3 e^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x + y = 3 e^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $x - y = 3 e^{- 2}$

Suggest Corrections

Similar questions

y = 2 e^{x} + 3 e^{2} x

y^{2} - 3 y + 2 y = 0

Find the equation of the normals to the curve y = x³ + 2x + 6 which are parallel to the line x + 14y + 4 = 0.

List-I	List-II
a) Equation of tangent to the curve $y = b e^{- x / a}$ at $x = 0$	1) $x - 2 y = 2$
b) Equation of tangent to the curve $y = x^{2} + 1$ at $(1, 2)$	2) $y = 2 x$
c) Equation of normal to the curve $y = 2 x - x^{2}$ at $(2, 0)$	3) $x - y = π$
d) Equation of normal to the curve $y = sin x$ at $x = π$	4) $\frac{x}{a} + \frac{y}{b} = 1$

Join BYJU'S Learning Program