Equation of a parabola whose vertex is (2,-3), axis is parallel to the x axis and lastusrectum 8 is

(y+3)²=8(x+2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(y+3)²=16(x-2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(y+3)²=8(x-2)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(y+3)²=32(x-2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
(y+3)²=8(x-2)

A=(2, -3)4a=8
Eqn of parabola is $(y + 3)^{2} = \pm 8 (x - 2)$

Suggest Corrections

Similar questions

(2, - 3)

8

(- 2, 1), (1, 2), (- 1, 3)

x^{2} - 2 x + 4 y + 9 = 0

y^{2} + 2 A x + 2 B y + C = 0

P Q

y = 2 x + k,

(- 2, 3)

x

2

Join BYJU'S Learning Program