Equation of circle center at origin and radius is $2$

x^{2} + y^{2} = 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} + y^{2} = 4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x^{2} + y^{2} = 2 \sqrt{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} + y^{2} = \sqrt{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $x^{2} + y^{2} = 4$
The equation of circle is $x^{2} + y^{2} = r^{2} x^{2} + y^{2} = 2^{2} x^{2} + y^{2} = 4$

Suggest Corrections

Similar questions

The equation of a circle of radius 1 touching the circles $x^{2} + y^{2} - 2 | x | = 0$ is

x^{2} + y^{2} = 4

\frac{π}{2}

x^{2} + y^{2} = 1.

x^{2} + y^{2} = r^{2}

^{'} θ^{'}

x^{2} + y^{2} = r^{2} {cos}^{2} (\frac{θ}{2})

x^{2} - y^{2} + 1 = 0

(1, 1)

x^{2} + y^{2} = 6

x^{2} + y^{2} - 6 x + 8 = 0

x^{2} + y^{2} + 2 y - 3 = 0,

Join BYJU'S Learning Program