Equation of circle whose parametric equations are x=5−5sint and y=4+5cost is
A
(x+5)2+(y−4)2=25
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B
(x−5)2+(y−4)2=25
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C
(x−5)2+(y+4)2=25
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D
(x+5)2+(y+4)2=25
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Solution
The correct option is B(x−5)2+(y−4)2=25 Given x=5−5sint,y=4+5cost ⇒x=5+5cos(π2+t),y=4+5sin(π2+t) ⇒(x−5)2+(y−4)2=52cos2(π2+t)+52sin2(π2+t) ⇒(x−5)2+(y−4)2=25