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Question

# Equation of line passing through mid point of intercepts made by circle x2+y2âˆ’4xâˆ’6y=0 on coordinate axes is

A
3x+2y12=0
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B
3x+y6=0
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C
3+4y12=0
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D
3x+2y6=0
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Solution

## The correct option is D 3x+2y−6=0Given circle x2+y2−4x−6y=0On putting y=0 in equation of circle we get the x intercept made by circlex2−4x=0x(x−4)=0x=0,4On putting x=0 in equation of circle we get the y intercept made by circley2−6y=0y(y−6)=0y=0,6Intercept made by circle on coordinate axes are (4,0) and (0,6)Equation of line through midpoint of intercepts in intercept form x2+y3=13x+2y=63x+2y−6=0

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