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Question

Equation of line passing through mid point of intercepts made by circle x2+y24x6y=0 on coordinate axes is

A
3x+2y12=0
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B
3x+y6=0
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C
3+4y12=0
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D
3x+2y6=0
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Solution

The correct option is D 3x+2y6=0
Given circle
x2+y24x6y=0
On putting y=0 in equation of circle we get the x intercept made by circle
x24x=0
x(x4)=0
x=0,4

On putting x=0 in equation of circle we get the y intercept made by circle
y26y=0
y(y6)=0
y=0,6

Intercept made by circle on coordinate axes are (4,0) and (0,6)
Equation of line through midpoint of intercepts in intercept form
x2+y3=1

3x+2y=6
3x+2y6=0

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