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Question

Equation of line passing through the point (1, 2) and perpendicular to the line y = 3x - 1 is

A
x + 3y + 7 = 0
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B
x + 3y - 7 = 0
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C
x + 3y = 0
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D
x - 3y = 0
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Solution

The correct option is C x + 3y - 7 = 0
y=3x1
General equation of line is y=mx+c
m=3
If two lines are perpendicular, thenm1m2=1
Slope of line perpendicular to y=3x1 will be 13
Equation of line y=13x+c
3y+x=c
This line passes through the point (1,2)
3(2)+1=c
c=7
Equation of line becomes
x+3y=7
x+3y7=0

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