Equation of motion of a body is $\frac{d v}{d t} = - 4 v + 8$ , where v is the velocity in m/s and t is the time in second. Initial velocity of the particle was zero. Then

the initial rate of change of acceleration of the particle is

8 m / s^{2}

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the terminal speed is 2 m/s

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Both A and B are correct

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Both A and B are wrong

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Solution

The correct option is B the terminal speed is 2 m/s
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Equation of motion of a body is dvdt=−4v+8, where v is the velocity in m/s and t is the time in second. Initial velocity of the particle was zero. Then

The correct option is B the terminal speed is 2 m/sundefined

Equation of motion of a body is $\frac{d v}{d t} = - 4 v + 8$ , where v is the velocity in m/s and t is the time in second. Initial velocity of the particle was zero. Then

The correct option is B the terminal speed is 2 m/s
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