Question

Equation of motion of a projectile is Y =Px + Qx² . Then the horizontal range of the projection is

Answer 1

Given that y = px + qx^2

According to Equation of Trajectory, y = x Tan (theta) [ 1 - x / R ]
This equation is needed to find horizontal range R.

y = px + qx^2 can also be written as,

y = xp + qx^2

= y = xp [ 1 + qx / p]

= y = xp [ 1 - (x / (-p/ q ))]

Now comparing this equation with Equation of trajectory, we get,

i) Tan (theta) = p = theta = Tan^-1 p

ii) Horizontal Range (R) = -p / q (Ans.)