Equation of plane which is parallel to XY-plane is
z = c ; where c is constant.
Let’s write the normal form of the plane.
(r - a) . n = 0
Where r is a general vector in that plane and a is fixed vector. So (r - a) will be the vector lying in that plane. And n vector is the normal vector to that plane.
For a plane parallel to XY plane -
Let r = xi + yj + zk
And a=a1i+a2j+a3k
So (r−a)=(x−a1)i+(y−a2)j+(z−a3)k
Here n will be = ck (As the normal to a plane which is parallel XY plane will be along Z- axis.)
Thus the equation of plane will be -
((x−a1)i+(y−a2)j+(z−a3)k).(ck)=0
Or (z−a3).c=0
Or z=a3
On comparing it with the given options we can say “C” is correct.